9.15 Interview Questions
Frequently asked and scenario-based Python string interview questions covering immutability, slicing, join() vs +=, and classic coding problems like palindrome, anagram, and longest common prefix.
Conceptual Questions
- Why are Python strings immutable, and what does that mean for methods like
.replace()? - What’s the difference between
find()andindex()? - Why is
s[::-1]the idiomatic way to reverse a string when there’s no.reverse()method? - Why is building a string with
+=in a loop worse than using.join()? - What’s the difference between
str.format()and an f-string?
Scenario-Based Questions
- A script processes a multi-gigabyte log file and needs to build a filtered output string line by line — how should it be built to avoid a performance cliff?
- An API response sometimes has extra whitespace or inconsistent casing in a status field — how would you normalize it reliably before comparing it?
- A regex pattern used inside a hot loop over thousands of log lines is running slowly — what’s the first optimization to check?
Coding Questions
- Check whether a given string is a palindrome, ignoring case and punctuation.
- Check whether two strings are anagrams of each other.
- Find the longest common prefix shared by a list of strings.
- Find the first non-repeating character in a string.
- Implement basic run-length string compression.
def longest_common_prefix(strs):
if not strs:
return ""
prefix = strs[0]
for s in strs[1:]:
while not s.startswith(prefix):
prefix = prefix[:-1]
return prefix
>>> longest_common_prefix(["flower", "flow", "flight"])
'fl'
Quick Interview Answer
“String interview questions cluster around three things: confirming immutability is understood (every method returns a new object;
.replace()on its own does nothing observable), whether the standard idioms are known instead of hand-rolled loops (s[::-1]for reversal,sorted(a) == sorted(b)for anagrams,''.join(...)over+=for building large strings), and classic coding problems — palindrome, anagram, longest common prefix, first non-repeating character — that test comfort combining slicing,Counter, andsorted()rather than writing everything from scratch.”
Common Mistakes
- Answering “strings are immutable so they can’t be modified at all” without the follow-up: every method still returns a new string, so
s.strip()is very much useful — just not in place. - Solving the longest-common-prefix question with nested loops comparing every character position across every string, instead of the simpler shrink-a-candidate-prefix approach.
- Reaching for a manual character-count loop for the anagram check instead of the one-line
sorted(a) == sorted(b)idiom.
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